UofT-DSI | SQL - Assignment 1

02_activities/assignments/Microcredential_Cohort/assignment1.sql

@@ -1,159 +1,209 @@
- /* ASSIGNMENT 1 */
---Please write responses between the QUERY # and END QUERY blocks
-/* SECTION 2 */
-
-
---SELECT
-/* 1. Write a query that returns everything in the customer table. */
---QUERY 1
-
-
-
-
---END QUERY
-
-
-/* 2. Write a query that displays all of the columns and 10 rows from the customer table, 
-sorted by customer_last_name, then customer_first_ name. */
---QUERY 2
-
-
-
-
---END QUERY
-
-
---WHERE
-/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. 
-Limit to 25 rows of output. */
---QUERY 3
-
-
-
-
---END QUERY
-
-
-
-/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
-filtered by customer IDs between 8 and 10 (inclusive) using either:
-	1.  two conditions using AND
-	2.  one condition using BETWEEN
-Limit to 25 rows of output.
-*/
---QUERY 4
-
-
-
-
---END QUERY
-
-
---CASE
-/* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
-Using the product table, write a query that outputs the product_id and product_name
-columns and add a column called prod_qty_type_condensed that displays the word “unit” 
-if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
---QUERY 5
-
-
-
-
---END QUERY
-
-
-/* 2. We want to flag all of the different types of pepper products that are sold at the market. 
-add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
-contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
---QUERY 6
-
-
-
-
---END QUERY
-
-
---JOIN
-/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
-vendor_id field they both have in common, and sorts the result by market_date, then vendor_name.
-Limit to 24 rows of output. */
---QUERY 7
-
-
-
-
---END QUERY
-
-
-
-/* SECTION 3 */
-
--- AGGREGATE
-/* 1. Write a query that determines how many times each vendor has rented a booth 
-at the farmer’s market by counting the vendor booth assignments per vendor_id. */
---QUERY 8
-
-
-
-
---END QUERY
-
-
-/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
-sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
-of customers for them to give stickers to, sorted by last name, then first name. 
-
-HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
---QUERY 9
-
-
-
-
---END QUERY
-
-
---Temp Table
-/* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: 
-Thomass Superfood Store, a Fresh Focused store, owned by Thomas Rosenthal
-
-HINT: This is two total queries -- first create the table from the original, then insert the new 10th vendor. 
-When inserting the new vendor, you need to appropriately align the columns to be inserted 
-(there are five columns to be inserted, I've given you the details, but not the syntax) 
-
--> To insert the new row use VALUES, specifying the value you want for each column:
-VALUES(col1,col2,col3,col4,col5) 
-*/
---QUERY 10
-
-
-
-
---END QUERY
-
-
--- Date
-/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
-
-HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
-and year are! 
-Limit to 25 rows of output. */
---QUERY 11
-
-
-
-
---END QUERY
-
-
-/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
-Remember that money spent is quantity*cost_to_customer_per_qty. 
-
-HINTS: you will need to AGGREGATE, GROUP BY, and filter...
-but remember, STRFTIME returns a STRING for your WHERE statement...
-AND be sure you remove the LIMIT from the previous query before aggregating!! */
---QUERY 12
-
-
-
-
---END QUERY
+ /* ASSIGNMENT 1 */
+--Please write responses between the QUERY # and END QUERY blocks
+/* SECTION 2 */
+
+
+--SELECT
+/* 1. Write a query that returns everything in the customer table. */
+--QUERY 1
+SELECT * FROM customer;
+--END QUERY
+
+
+/* 2. Write a query that displays all of the columns and 10 rows from the customer table, 
+sorted by customer_last_name, then customer_first_ name. */
+--QUERY 2
+SELECT * 
+FROM customer
+ORDER BY customer_last_name,customer_first_name
+LIMIT 10;
+--END QUERY
+
+
+--WHERE
+/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. 
+Limit to 25 rows of output. */
+--QUERY 3
+SELECT * 
+FROM customer_purchases
+WHERE product_id IN (4,9)
+LIMIT 25;
+--END QUERY
+
+
+
+/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
+filtered by customer IDs between 8 and 10 (inclusive) using either:
+	1.  two conditions using AND
+	2.  one condition using BETWEEN
+Limit to 25 rows of output.
+*/
+--QUERY 4
+SELECT 
+product_id,
+vendor_id,
+market_date,
+customer_id,
+quantity,
+cost_to_customer_per_qty,
+transaction_time,
+quantity * cost_to_customer_per_qty AS price 
+FROM customer_purchases
+WHERE customer_id BETWEEN 8 AND 10
+LIMIT 25;
+--END QUERY
+
+
+--CASE
+/* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
+Using the product table, write a query that outputs the product_id and product_name
+columns and add a column called prod_qty_type_condensed that displays the word “unit” 
+if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
+--QUERY 5
+SELECT 
+product_id
+,product_name
+,CASE 	
+	WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+	END AS prod_qty_type_condensed
+FROM product;
+--END QUERY
+
+
+/* 2. We want to flag all of the different types of pepper products that are sold at the market. 
+add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
+contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
+--QUERY 6
+SELECT 
+product_id
+,product_name
+,CASE WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+	END AS prod_qty_type_condensed
+,CASE WHEN product_name LIKE '%pepper%' THEN 1
+	ELSE 0
+	END AS pepper_flag
+FROM product;
+--END QUERY
+
+
+--JOIN
+/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
+vendor_id field they both have in common, and sorts the result by market_date, then vendor_name.
+Limit to 24 rows of output. */
+--QUERY 7
+SELECT 
+vd.vendor_id,
+vendor_name,
+vendor_type,
+vendor_owner_first_name,
+vendor_owner_last_name,
+booth_number,
+market_date
+
+FROM vendor AS vd
+INNER JOIN vendor_booth_assignments AS vb
+	ON vd.vendor_id = vb.vendor_id
+ORDER BY market_date, vendor_name
+LIMIT 24;
+--END QUERY
+
+
+
+/* SECTION 3 */
+
+-- AGGREGATE
+/* 1. Write a query that determines how many times each vendor has rented a booth 
+at the farmer’s market by counting the vendor booth assignments per vendor_id. */
+--QUERY 8
+SELECT 
+vendor_id, 
+COUNT(booth_number) AS rent_booth
+
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
+--END QUERY
+
+
+/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
+sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
+of customers for them to give stickers to, sorted by last name, then first name. 
+
+HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
+--QUERY 9
+SELECT
+c.customer_last_name,
+c.customer_first_name,
+c.customer_id,
+c.customer_postal_code,
+ROUND(SUM(quantity * cost_to_customer_per_qty),2) AS total_spent
+
+FROM customer AS c
+INNER JOIN customer_purchases AS cp 
+	ON c.customer_id = cp.customer_id
+GROUP BY c.customer_id
+HAVING total_spent > 2000
+ORDER BY customer_last_name, customer_first_name;
+--END QUERY
+
+
+--Temp Table
+/* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: 
+Thomass Superfood Store, a Fresh Focused store, owned by Thomas Rosenthal
+
+HINT: This is two total queries -- first create the table from the original, then insert the new 10th vendor. 
+When inserting the new vendor, you need to appropriately align the columns to be inserted 
+(there are five columns to be inserted, I've given you the details, but not the syntax) 
+
+-> To insert the new row use VALUES, specifying the value you want for each column:
+VALUES(col1,col2,col3,col4,col5) 
+*/
+--QUERY 10
+DROP TABLE IF EXISTS temp.new_vendor;
+
+CREATE TABLE temp.new_vendor AS
+SELECT * FROM vendor;
+
+INSERT INTO temp.new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES(10,'Thomass Superfood Store','Fresh Focused','Thomas','Rosenthal');
+
+SELECT	* from temp.new_vendor;
+--END QUERY
+
+
+-- Date
+/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
+
+HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
+and year are! 
+Limit to 25 rows of output. */
+--QUERY 11
+SELECT 
+customer_id,
+strftime('%m', market_date) AS month,
+strftime('%Y', market_date) AS year
+
+FROM customer_purchases
+LIMIT 25;
+--END QUERY
+
+
+/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
+Remember that money spent is quantity*cost_to_customer_per_qty. 
+
+HINTS: you will need to AGGREGATE, GROUP BY, and filter...
+but remember, STRFTIME returns a STRING for your WHERE statement...
+AND be sure you remove the LIMIT from the previous query before aggregating!! */
+--QUERY 12
+SELECT 
+customer_id,
+strftime('%m', market_date) AS month,
+strftime('%Y', market_date) AS year,
+SUM(quantity * cost_to_customer_per_qty) AS total_spent
+
+FROM customer_purchases
+WHERE strftime('%m', market_date) = '04'
+  AND strftime('%Y', market_date) = '2022'
+GROUP BY customer_id;
+--END QUERY