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21606.py
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94 lines (72 loc) · 1.91 KB
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# 아침 산책
# 새로운 알고리즘 200점
# 실외에서 갈 수 있는 경우의 수 n 을 알아내서
# n * (n-1) 으로 경우의 수만 계산하는 방법
import sys
sys.setrecursionlimit(10**6)
input = sys.stdin.readline
N = int(input())
A = input().rstrip()
indoor = [0] * (N+1)
visited = [False] * (N+1)
graph = [[] for _ in range(N+1)]
answer = 0
for i in range(len(A)):
if A[i] == '1':
indoor[i+1] = 1
for _ in range(N-1):
vertex_a, vertex_b = map(int, input().split())
graph[vertex_a].append(vertex_b)
graph[vertex_b].append(vertex_a)
def dfs(vertex):
res = 0
for i in graph[vertex]:
if indoor[i] == 0:
if not visited[i]:
visited[i] = 1
res += dfs(i)
else:
res += 1
return res
for i in range(1, N+1):
if indoor[i] == 0:
if not visited[i]:
visited[i] = 1
res = dfs(i)
answer += res * (res-1)
else:
for next_node in graph[i]:
if indoor[next_node] == 1:
answer += 1
print(answer)
# 60점 코드
# import sys
# sys.setrecursionlimit(10**6)
# input = sys.stdin.readline
# N = int(input())
# A = input().rstrip()
# indoor = [0] * (N+1)
# visited = [[False] * (N+1) for _ in range(N+1)]
# graph = [[] for _ in range(N+1)]
# answer = 0
# for i in range(len(A)):
# if A[i] == '1':
# indoor[i+1] = 1
# for _ in range(N-1):
# vertex_a, vertex_b = map(int, input().split())
# graph[vertex_a].append(vertex_b)
# graph[vertex_b].append(vertex_a)
# def dfs(start, vertex):
# global answer
# visited[start][vertex] = True
# for i in graph[vertex]:
# if not visited[start][i]:
# if indoor[i] == 0:
# dfs(start, i)
# else:
# answer += 1
# return
# for i in range(1, N+1):
# if indoor[i] == 1:
# dfs(i, i)
# print(answer)